y^2+y-19740=0

Solution for y^2+y-19740=0 equation:

y^2+y-19740=0

a = 1; b = 1; c = -19740;
Δ = b2-4ac
Δ = 12-4·1·(-19740)
Δ = 78961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{78961}=281$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-281}{2*1}=\frac{-282}{2}
=-141
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+281}{2*1}=\frac{280}{2}
=140
$